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Nina [5.8K]
3 years ago
5

Solve using elimination. –4x + 9y = –18 –x − y = –11

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
To do elimination, you need to get same coefficient before the variable
Multiply (-x-y = -11) by 4
-4x + 9y = -18
-4x - 4y = -44
Now subtract
13y = 26, y = 2
Plug in y = 2 for any of the two equation
-x - 2 = -11
-x = -9, x = 9

Solution: x = 9, y = 2
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The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?
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First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.


If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.





8 0
4 years ago
Read 2 more answers
Evaluate the following 12!/9!3!
IRINA_888 [86]
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5 0
3 years ago
Find each marked side or angle and show the step by step​
goldenfox [79]

Answer:

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A triangle with vertices located at (−2, −2) and (4, −2) has an area of 24 square units. Which is one possible location of the o
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Answer: A) (4, 6)

Step-by-step explanation:

1. You can plot the given points (-2,-2) and (4,-2), as you can see in the first graph attached.

2. The formula for calculate the area of a triangle is:

A=\frac{bh}{2}

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3. As you can see in the first graph, the lenght of the base is:

b=6units

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h=\frac{2A}{b}=\frac{2(24units^{2})}{6units}=8units

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(-2,-2+8)=(-2,6) (This is not an option)

(4,-2+8)=(4,6) (Option A. This is the answer).

4. Then, the triangle is shown in the second graph.

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4 years ago
Which statements are true about the graph of y &lt; 2/3x + 1? Check all that apply.
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