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3 years ago

11

Meiling needs 5 dollars 35 cents to buy a ticket to a show. In her wallet, she finds 2 dollar bills, 11 dimes, and 5 pennies. Ho

w much more money does Meiling need to buy the ticket?

1 answer:

Llana [10]3 years ago

5 0

Answer:

no she needs $2.20 more

Step-by-step explanation:

2+ 1.10+.05= $3.15

$5.35 - $3.15 = the answer

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Who is a consumer? A. a person who buys items in a store B. a person who owns a store C. a person who works at a store

tino4ka555 [31]

A) A person who buys items in the store

A consumer is someone who takes , or in this case buys. I hope I helped!

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3 years ago

WORTH 60 POINTS! PLZ HELP! BRAINLIEST OPPORTUNITY!

makkiz [27]

Answer:

x = 10

Step-by-step explanation:

2) -3x + 17 = -x - 3

4) 20 = 2x

1) -3x + 12 + 5 = -x -3

5) 10 = x

3) 17 = 2x - 3

<u>-3(x - 4) + 5 = -x - 3</u>

<u>-3x + 12 + 5 = -x - 3</u>

<u>-3x + 17 = -x -3</u>

<em>+3x +3x</em>

<u>17 = 2x - 3</u>

<em>+3 + 3</em>

<u>20 = 2x</u>

<u>10 = x</u>

<u />

I hope that this helps! :)

5 0

3 years ago

For which angle theta is cos theta =-1?<br>a) 270<br>b) 360<br>c) 450<br>d) 540

yanalaym [24]

Answer:

540°.

Step-by-step explanation:

On a unit circle, cos θ = -1 at 180°.

However, cos θ has a period of 2π, or 360°. This means that cos θ will equal to -1 again after 2π.

To solve for the angle:

180° + 360° = 540°. This is the next angle at which cos θ = -1.

7 0

3 years ago

Read 2 more answers

PLEASE HELP OUT!!! im super lost.

Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 - (-3)

f(-3) = 5 +3

f(-3) = 8

3 0

3 years ago

A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200

kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$ = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

( 10 ±4 )

( 10 -4 , 10+4)

( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0

3 years ago