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Akimi4 [234]
3 years ago
7

Help me u know who you are

Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

B

Step-by-step explanation:

In a parellelogram opposite angles are always equal

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Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
jeka94

by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression  x2 + 20 = 2x or , x^2 + 20 = 2x .

We know that Quadratic formula is :

x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

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a=1\\b=-2\\c=20

Putting this value in equation x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} :

⇒ x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

⇒ x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}

⇒ x = \frac{2 \pm \sqrt{4-80}}{2}

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⇒ x = 1 \pm (1)i\sqrt{19}}

Therefore , by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

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