All the equations can be graphed and solved by graphing. They can also be solved using various other methods
Answer:
1.) 6
2.) -1
3.) 36
4.) 1/3
5.) 90
Step-by-step explanation:
1.) -12/a
-12/a -> -12/2
=6
2.) a+ (-b)
a+(-b) -> 2+(-3)
=-1
3.) 3a (12-2b)
3a(12-2b) -> 3(2) (12-2x3)
6(12-6)
6(6)
=36
4.) 2a-c/b
2a-c/b -> 2(2)-5/3
4-5/3
=1/3
5.) 3abc
3abc-> 3x2x3x5
=90
The answer and workings are in the document below. Please open it up in a new window to see it in full.
Answer:
1/100000
Step-by-step explanation:
1/10*1/10*1/1000=1/100*1/1000=1/100000
Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.