2•14 =28, 2• 270=540, 2•141=282, 2 is the GCF
Answer:
A= 0.5 and B= 4040
Step-by-step explanation:
If you write out the equation and rearrange a little it gets easier to understand.
( a + b) + (a*b) + (a - b) you can rewrite this as
a + b + a - b + (a*b) this is the same as 2a + ab = 2021
The way I looked at it is to figure out how to get that number 1 at the end.
The number 2020 is easy to get to. How can you get the number 1 using either 2a or ab.
I looked at a = 0.5. 2 times 0.5 would be 1.
So now what would b have to be? We can get the 1 at the end with the 2a part of the equation so now we have to get ab = 2020.
b = 2020/a which using our a = 0.5, you can see that b would have to equal 4040. Test it all out in your equation.
0.5 + 4040 + (0.5 * 4040) + 0.5 - 4040
4040.5 + (2020) - 4039.5 = 2021
So A = 0.5 and B = 4040
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
I'm not good at graphing, but desmos.com is an online graphing calculator that works really well.
I THINK ITS C.135 DEGREES
