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sergejj [24]
2 years ago
12

Helppp it’s due in a couple minutes!!!

Mathematics
2 answers:
trasher [3.6K]2 years ago
8 0
Not my work but found answer key to answer u need.

Y_Kistochka [10]2 years ago
8 0

Answer:

          1

         10

         10

200

200

----------

5 divided by 2105

1000 - 2105 = 1105

1105 - 1000 = 105

105 - 50 = 55

55 - 50 = 5

5 - 5 = 0

Step-by-step explanation:

put that exactly and hopefully you get it in time and good luck!

( p.s ) just time the number or in this case 5 by something that will get you close to the number your subtracting.

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What is the GCF for 282, 540, and 28
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2 years ago
A + B
Klio2033 [76]

Answer:

A= 0.5 and B= 4040

Step-by-step explanation:

If you write out the equation and rearrange a little it gets easier to understand.

( a + b) + (a*b) + (a - b)  you can rewrite this as

a + b + a - b + (a*b)  this is the same as 2a + ab = 2021

The way I looked at it is to figure out how to get that number 1 at the end.

The number 2020 is easy to get to.  How can you get the number 1 using either 2a or ab.

I looked at a = 0.5.   2 times 0.5 would be 1.

So now what would b have to be?  We can get the 1 at the end with the 2a part of the equation so now we have to get ab = 2020.

b = 2020/a  which using our a = 0.5, you can see that b would have to equal 4040.  Test it all out in your equation.

0.5 + 4040 + (0.5 * 4040) + 0.5 - 4040

4040.5 + (2020) - 4039.5 = 2021

So A = 0.5  and B = 4040

4 0
3 years ago
g Programs submitted by programs in a computer science course are examined for syntax errors and logic errors. Suppose 36% of al
Llana [10]

Answer:

The answer is below

Step-by-step explanation:

Let S denote syntax errors and L denote logic errors.

Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56

a) The probability a program contains both error types = P(S ∩ L)

The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L)  - P(L) = 56% - 47% = 9%

The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L)  - P(S) = 56% - 36% = 20%

P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%

b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44

c)  The probability a program has logic errors, but not syntax errors =   P(S' ∩ L) = P(S ∪ L)  - P(S) = 56% - 36% = 20%

d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44

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