Add the two expressions.<br><br> 6q + 1 and q + 11

In this we have to apply pythagoras theorem because it says tat the square of hypotenuse is equal to the sum of squares of base and perpendicular of that right angled triangle.

$H^{2} =P^{2} +B^{2}$

H=c

P=7 feet

B=7 feet.

Put the values in the above rule:

$c^{2} =7^{2} +7^{2}$

$c^{2}$ =49+49

$c^{2}$ =98

c=9.899

After rounding off to nearest tenth we will get c=9.9.

Hence the value of c is 9.9 which is the length of hypotenuse.

Learn more about pythagoras theorem at brainly.com/question/343682

#SPJ4

4 0

2 years ago

By determining f prime left parenthesis x right parenthesis equals ModifyingBelow lim With h right arrow 0 StartFraction f left

aniked [119]

Answer:

70 is answer

Step-by-step explanation:

Given that a function in x is

$f(x) = 5x^2$

we have to find f'(7)

we know by derivative rule derivative of a function is

$f'(x) = lim_({h-->0}) \frac{f(x+h)-f(x)}{h}$

For finding out at 7 we replace x by 7

$f'(7) = lim_({h-->0}) \frac{f(7+h)-f(7)}{h}$

= $lim\frac{5(7+h)^2-5*7^2}{h} \\= lim \frac{10h*7+h^2}{h} \\= 70+h = 70$

So f'(7) = 70

answer is 70

3 0

3 years ago

Read 2 more answers

SOLVE FOR X??? <br><br><img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%20%2B2%20%3D%5Cfrac%7Bx%7D%7B4%7D%2B3" id="TexFor

natima [27]

Answer:

$\boxed{ \bold{ \boxed{ \sf{1. \: \: \: \: \: x = 12}}}}$

$\boxed{ \bold{ \boxed{ \sf{2. \: \: \: \: \: x = 3}}}}$

Step-by-step explanation:

$\sf{1. \: \: \: \: \frac{x}{3} + 2 = \frac{x}{4} + 3}$

Move x / 4 to left hand side and change its sign

Similarly, move 2 to right hand side and change it's sign

$\longrightarrow{ \sf{ \frac{x}{3} - \frac{x}{4} = 3 - 2}}$

Take the L.C.M of 3 and 4

L.C.M of 3 and 4 = 12

$\longrightarrow{ \sf{ \frac{x \times 4 - x \times 3}{12} = 3 - 2}}$

$\longrightarrow{ \sf{ \frac{4x - 3x}{12} = 3 - 2}}$

$\longrightarrow{ \sf{ \frac{x}{12} = 3 - 2}}$

Subtract 2 from 3

$\longrightarrow{ \sf{ \frac{x}{12} = 1}}$

Do cross multiplication

$\longrightarrow{ \sf{x = 1 \times 12}}$

$\longrightarrow { \sf{x = 12}}$

--------------------------------------------------------------------

$\sf{2. \: \: \: \: 3(4 + 2x) = 33 - x }$

Distribute 3 through the parentheses

$\longrightarrow{ \sf{12 + 6x = 33 - x}}$

Move x to left hand side and change it's sign

Similarly, move 12 to right hand side and change it's sign

$\longrightarrow{ \sf{6x + x = 33 - 12}}$

Collect like terms

$\longrightarrow{ \sf{7x = 33 - 12}}$

Subtract 12 from 33

$\longrightarrow{ \sf{7x = 21}}$

Divide both sides by 7

$\longrightarrow{ \sf{ \frac{7x}{7} = \frac{21}{7} }}$

Calculate

$\longrightarrow{ \sf{x = 3}}$

Hope I helped!

Best regards! :D

4 0

3 years ago

Add the two expressions. 6q + 1 and q + 11