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notsponge [240]
3 years ago
14

Please please please help

Mathematics
2 answers:
tia_tia [17]3 years ago
3 0
It’s false!!! Hope this helped;)
yarga [219]3 years ago
3 0

Answer:

False

Step-by-step explanation:

4x+4+5y=9xy+4

Step 1: Add -9xy to both sides.

4x+5y+4+−9xy=9xy+4+−9xy

−9xy+4x+5y+4=4

Step 2: Add -5y to both sides.

−9xy+4x+5y+4+−5y=4+−5y

−9xy+4x+4=−5y+4

Step 3: Add -4 to both sides.

−9xy+4x+4+−4=−5y+4+−4

−9xy+4x=−5y

Step 4: Factor out variable x.

x(−9y+4)=−5y

Step 5: Divide both sides by -9y+4.

x(−9y+4)

−9y+4

=

−5y

−9y+4

x=

−5y

−9y+4

Answer:

x=

−5y

−9y+4

this does not add up as in um.. i forgot the word- but yea its false

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shtirl [24]

Answer:

y=8x

Step-by-step explanation:

Hope this helps you

8 0
3 years ago
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Three consecutive odd integers are such that the square of the third integer is 1515 greater than greater than the sum of the sq
Ksju [112]
Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer

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(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0

using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
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the answer is
the first odd integer x is 1
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7 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
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Brums [2.3K]

The slope of the red line is 5. The correct answer is option B. 5

Two parallel lines, always have the same slope. Since the green and red line are parallels and the green line has slope 5, the slope of the red line is also 5.

5 0
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The solution as in where do they intersect? if so, it would be 0.0769 and -0.0769
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