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3 years ago

How to solve:

Mathematics

2 answers:

natima [27]3 years ago

7 0

Let the first be x and the second be x + 4
x+ x + 4 = 56
2x+4 = 56
2x = 52
∴x= 26

please mark as brainliest

r-ruslan [8.4K]3 years ago

4 0

X= 1st number (26)
4+x=2nd number (30)
4+x+x=56
4+2x=56
2x=52
x=26

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3 years ago

How would I solve y-8+3(y+4)

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3 years ago

rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden

Ray Of Light [21]

It is given that the area of the circular garden = 100 $ft^2$

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3 years ago

Read 2 more answers

One number is 3 less than twice another. If their sum is 39 find the numbers

DedPeter [7]

Answer:

The numbers are 14 and 25

Step-by-step explanation:

Let one of the numbers be x. The second number we are told is 3 less than twice x. The second number will thus be;

2x - 3

The sum of the numbers is thus;

x + (2x - 3) = 3x - 3

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3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

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Taking ln both sides,

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$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

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$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago