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Romashka [77]
4 years ago
5

Please help me with this question Screenshot is included.

Mathematics
1 answer:
UNO [17]4 years ago
3 0

Answer:

D

Step-by-step explanation:

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1000 cylindrical metal bars of length 120 m and diameter 0.2 m , as shown below, are to be used in constructing a bridge. He bar
Troyanec [42]

Answer:

the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

Step-by-step explanation:

Given that:

1000 cylindrical metal bars have :

a length of 120 m

and a diameter of  0.2 m

The volume of the cylindrical bar can be calculated by the formula:

V= \pi r^2 h

where ;

radius   r=\dfrac{d}{2}

r = \dfrac{0.2}{2}

r = 0.1 m

the length of the cylindrical metal bars is equal to the height of the metal bar = 120 m

Thus the volume can now be calculated as follows:

V= \pi* 0.1^2*120

V = 3.77 m³

So; from the given information.

One litre of paint will cover 4m³

and we want to find how many litres of paint will be used for the 1000 cylindrical bars.

If        1 litre = 4m³

Then  x litre = 3.77 m³

4x = 1 × 3.77

x = \dfrac{1*3.77 }{4}

x = 0.9425 litres

x = 1 litres to the nearest litres.

Thus ; the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

4 0
4 years ago
Help me please.
PilotLPTM [1.2K]

Answer:

C) sin 55

Step-by-step explanation:

7 0
3 years ago
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Whats the Quotient and Remainder: of 64,877 divided by 9
professor190 [17]

Answer: 7208 remainder 5

Step-by-step explanation:

5 0
3 years ago
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Simplify $\sqrt[3]{\frac{9\sqrt{5}}{2\sqrt{3}}\cdot\frac{5\sqrt{2}}{8\sqrt{2}}}$ and rationalize the denominator. The result can
Alecsey [184]

Answer:

15+6+2=23

Step-by-step explanation:

\sqrt[3]{\frac{9\sqrt{5}}{2\sqrt{3}}\cdot\frac{5\sqrt{2}}{8\sqrt{2}}}\\=\sqrt[3]{\frac{9\sqrt{5}}{2\sqrt{3}}\cdot\frac{5}{8}}\\=\sqrt[3]{\frac{45\sqrt{5}}{16\sqrt{3}}}\\=\sqrt[3]{\frac{45\sqrt{15}}{16}}\\=\sqrt[3]{\frac{3\cdot\sqrt{15^3}}{16}}\\=\frac{\sqrt[3]{3}\cdot\sqrt{15}}{2\cdot\sqrt[3]{2}}\\=\frac{\sqrt[3]{6}\cdot\sqrt{15}}{2}

we want it in the form of \frac{\sqrt{a}\sqrt[3]{b}}{c}, so a = 15, b=6, c=2

also this is the minimum possible value, as we cannot simplify it further

7 0
2 years ago
I need help please this is quite hard for me
creativ13 [48]
Use photomath because it is very helpful bro
4 0
3 years ago
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