X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
can you show me what the math problem is?
The question as you wrote it doesn't fit the answers. However, one of the answers fits if you meant
"elapsed time from 5:34 to 10:11".
There are many ways to do this. Try first taking the time from 5:34 to 6:11, and after that finding the time from 6:11 to to 10:11.
In a way, 6:00 is the same thing as 5:60. Add 11 to that and you can see that 6:11 is the same as 5:71. Now that you have an easy way to find the time from 5:34 to 6:11.
6:11 - 5:34 isn't easy.
But 5:71 - 5:34 is quite easy. 71 - 34 is 37.
So, from 5:34 to 6:11 there are 37 minutes.
Now the easy part, finding the time from 6:11 to 10:11. Since the minutes are the same, just subtract the hours. 10 - 6 = 4 hours.
Now you have the hours and minutes, which number 4 hours and 37 minutes.
Answer:
the slope would be -1/2.
Step-by-step explanation:
