Answer:
P(X = 0) = 0.064
P(X = 1) = 0.288
P(X = 2) = 0.432
P(X = 3) = 0.216
Step-by-step explanation:
Given that the probability of a wafer passing the test = 0.6, hence the probability of a wafer failing the test = 1 - 0.6 = 0.4.
Let X be the number of wafers that pass the test, since they are 3 wafers, hence X = 0, 1, 2, 3
Probability that all the three wafers failed the test = P(X = 0) = 0.4 × 0.4 × 0.4 = 0.064
Probability that all one wafer passed the test = P(X = 1) = (0.6 × 0.4 × 0.4) + (0.4 × 0.6 × 0.4) + (0.4 × 0.4 × 0.6) = 0.288
Probability that two wafers passed the test = P(X = 2) = (0.6 × 0.6 × 0.4) + (0.4 × 0.6 × 0.6) + (0.6 × 0.4 × 0.6) = 0.432
Probability that all three wafers passed the test = P(X = 3) = (0.6 × 0.6 × 0.6) = 0.216
<span>9/10 / 5/8
=</span><span>9/10 x 8/5
=36/25
= 1 11/25 (1 and 11/25)</span>
I believe that the answer is b
Answer:
BC
AB
AC
Step-by-step explanation:
The smallest side is BC
The next smallest side is AB
The largest side is AC
I think the answer is 0.25 seconds later
Hope this helped
