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Vedmedyk [2.9K]
3 years ago
13

The radius of a circle is increased from 8.008.00 to 8.038.03 m. Estimate the resulting change in​ area, and then express the es

timate as a percentage of the​ circle's original area. The estimated change in area is nothing msquared2.
Mathematics
1 answer:
Reika [66]3 years ago
7 0

Answer:

Step-by-step explanation:

The area of a circle is expressed as

Area = πr^2

Where r = radius of the circle

π = constant = 3.14

The radius of a circle is increased from 8.00800 to 8.03803 m. This means that the original radius of the circle is 8.00800 and the new radius of the circle is 8.03803

Area of original circle =

3.14 × 8.00800^2 = 201.36212096

Area of new circle =

3.14 × 8.03803^2 = 202.87516852203

Increase in area = 202.87516852203 - 201.36212096

= 1.51304756203

Expressing the change as a percentage, it becomes

1.51304756203/201.36212096 ×100

Percentage change = 0.75 %

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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0
3 years ago
In the game of baseball, there are 3 in outs per inning . A pitcher who pitches 4 innings and gets two batters out in the fifth
weeeeeb [17]

Answer: Yes, it is correct

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2 years ago
7.60. When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. S
Lelechka [254]

Answer:

The number of meters Robert will beat Sam is 12 meters.

Step-by-step explanation:

Given:

When Paul crossed the finish line of a 60-meter race, he was ahead of Robert by 10 meters and ahead of Sam by 20 meters. Suppose Robert and Sam continue to race to the finish line without changing their rates of speed.

Find:

the number of meters by which Robert will beat Sam

Step 1 of 1

When Paul finishes, Robert has run 60-10=50 meters and Sam has run 60-20=40 meters.

Therefore, when Robert and Sam run for the same amount of time, Sam covers $\frac{40}{50}=\frac{4}{5}$ of the distance that Robert covers. So, while Robert runs the final 10 meters of the race, Sam runs $\frac{4}{5} \cdot 10=8$ meters.

This means Robert's lead over Sam increases by 2 more meters, and he beats Sam by 10+2=12 meters.

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1 year ago
How to solve the exponential equation for 3^k2 • 3^-k+2 = 81
wariber [46]

Answer:

k=2

Step-by-step explanation:

3^k*2 * 3^-k+2 = 81

Factor out 81 to be : 3^4

Rewrite the equation:

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Simplify : k+2 = 4

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