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Savatey [412]
3 years ago
8

Can u guys help me with this problem?

Mathematics
1 answer:
yan [13]3 years ago
3 0

I'll come up with the intercepts and the two intercept form.  You'll have to connect the dots to draw the line.

5.

3x-2y = -6

Dividing by -6,

\dfrac{x}{-2} + \dfrac{y}{3} = 1

That's an x intercept at (-2,0) and a y intercept at (0,3)

Connect the dots and beyond

6.

\frac x 2 + \frac y 4 = 1

That's already in two-intercept form, connect (2,0) and (0,4)

7.

5x + 2y = -10

Divide by -10

\frac{x}{-2} + \frac{y}{-5}  =1

Connect (-2,0) and (0,-5)


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Help please! I’ll give brainliest too!
DIA [1.3K]

Answer:

y-intercept: -5

Slope: 4

Equation: y = 4x - 5

Step-by-step explanation:

✔️The y-intercept is the value of y when x = 0. From the table of values, it shows that when x = 0, y = -5. Therefore:

y-intercept (b) = -5

✔️using two pairs from the table, (1, -1) and (2, 3):

Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 -(-1)}{2 - 1} = \frac{4}{1} = 4

Slope = 4

✔️To write an equation for the function, substitute m = 4, and b = -5 into y = mx + b.

Thus:

y = 4x +(-5)

y = 4x - 5

7 0
3 years ago
HELPPPPP MEEEEE PLEASEEEE
Korolek [52]

Answer:

I don't know sooooooooop

mark me as brainliest ok understood

8 0
2 years ago
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in the given kite SZ= 10yards , WZ = 10 yards TZ=12 yards , and RZ=32 yards Determine the area of the kite
Fynjy0 [20]

If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:

... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)

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gulaghasi [49]

Answer:

no

Step-by-step explanation:

because I no and nono and y

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