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Deffense [45]
3 years ago
8

Ahmed is solving the following equation for xxx.

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer:

No

Step-by-step explanation:

An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.

Ahmed is solving 2\sqrt[3]{x-7}+11=3 for x.

His steps were:

\begin{aligned}2\sqrt[3]{x-7}&=-8\\  \sqrt[3]{x-7}&=-4\\  \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\  x-7&=-64 \end{aligned}

Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.

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