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saul85 [17]
3 years ago
15

What are the zeros of this function

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0

Answer:

B x=3 and x=6

Step-by-step explanation:

The zeros of the function are where the function crosses the x axis

Looking at the graph

This function crosses at x=3 and x = 6

Anestetic [448]3 years ago
4 0

Answer:

X =3 and x =6

Step-by-step explanation:

Just look at the line where they cross another line,

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One inch. There are 2.54 cm in an inch.
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ruth had a ribbon that was 9 yards long. she cut the ribbon into pieces that were 1/6 yard long. how many pieces of ribbon does
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Answer:

54

Step-by-step explanation:

6            x       9         =         54

she can      there are

make 6       9 yards

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3 years ago
A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace
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D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
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P(dDD)=85/100*15/99*14/99=17/924
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5 0
4 years ago
Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

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3 years ago
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Answer:

It is vertically stretched by a factor of 200 and shifted 10 units up.

Step-by-step explanation:

cool like that

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2 years ago
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