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Reptile [31]
2 years ago
14

Find the volume of this 1/4 cylinder after removing the inner part​

Mathematics
1 answer:
denpristay [2]2 years ago
3 0

28-21=7

thickness = 2x7=14

volume =  \frac{1}{4} \pi \times h( {ro}^{2}  -  {ri}^{2} ) \\ =  \frac{1}{4}  \times 3.14 \times 14( {35}^{2}  -  {21}^{2} ) = 8620.276

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The ratio of the measures of the sides of a
ANTONII [103]

Answer:

The length of the sides are 8 , 32 , 36

Step-by-step explanation:

Ratio of sides = 2  : 8 : 9

The sides are 2x , 8x , 9x

Perimeter of triangle = 76 inches

2x+ 8x + 9x  = 76

              19x = 76

                 x = 76/19

x = 4

2x = 2*4 = 8

8x = 8 * 4 = 32

9x = 9 * 4 = 36

6 0
3 years ago
Read 2 more answers
(Please help)Choose the correct answer and please explanation each (Brainliest)
Vesnalui [34]

Answer:

1. C

2. D

3. C

Explanation:

1. Girls = 12 plus twice the number of boys, so  C. y = 12 + 2x.

2. You have to see which point has the second value being greater than the first value:

 A) -1 > -2 is not true

 B) 0 > 1 is not true

 C) 2 > 3 is not true

 D) 8 > 4 is true, so it's D

3. Add the two values and see if it's less than 5

 A) -1-4 < 5 is true

 B) 0 + 4 < 5 is true

 C) 1 + 7 < 5 is not true, so this is the answer

 D) 2 + 2 < 5 is true

3 0
2 years ago
4p + 1 &gt; −7 or 6p + 3 &lt; 33?
aleksandr82 [10.1K]
P>-2 or p < 5 is your answer 
4 0
3 years ago
Show your work (19−7)^( (2) ) −8*3+4*3−5
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

1 Simplify 19-7 to 12.

12^2−8×3+4×3−5

2 Simplify 12^2 to 144

144−8×3+4×3−5

3 Simplify 8×3 to 24.

144−24+4×3−5

4 Simplify 4×3 to 12.

144−24+12−5

5 Simplify 144-24 to 120.

120+12-5

6 Simplify 120+12 to 132.

132-5

7 Simplify.

127

3 0
2 years ago
Jason knows that the equation to calculate the period of a simple pendulum is , where T is the period, L is the length of the ro
Brrunno [24]

<u>Answer-</u>

\boxed{\boxed{L=\dfrac{g}{4\pi^2 f^2}}}

<u>Solution-</u>

The equation for time period of a simple pendulum is given by,

T=2\pi \sqrt{\dfrac{L}{g}}

Where,

T = Time period,

L = Length of the rod,

g = Acceleration due to gravity.

Frequency (f) of the pendulum is the reciprocal of its period, i.e

f=\dfrac{1}{T}\ \Rightarrow T=\dfrac{1}{f}

Putting the values,

\Rightarrow \dfrac{1}{f}=2\pi \sqrt{\dfrac{L}{g}}

\Rightarrow (\dfrac{1}{f})^2=(2\pi \sqrt{\dfrac{L}{g}})^2

\Rightarrow \dfrac{1}{f^2}=4\pi^2 \dfrac{L}{g}

\Rightarrow L=\dfrac{g}{4\pi^2 f^2}

8 0
3 years ago
Read 2 more answers
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