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3 years ago

Journalise the followung transactions.

Business

1 answer:

katovenus [111]3 years ago

3 0

Answer:

Explanation:

S/No Date Transaction Dr($) Cr($)

1 Oct.1 Rent Expense 3,600

Cash 3,600

2. Oct.3 Advert. Expenses 1,200

Cash 1,200

3. Oct.5 Supplies 750

Cash 750

4 Oct.6 Office equipment 8000

Accounts Payable 8,000

5 Oct.10 Cash 1 4,800

Accounts receivable 14,800

6 Oct.15 Accounts payable 7,110

Cash 7,110

7. Oct.27 Miscellaneous 400

Cash 400

8 Oct.30 Utilities Expenses 250

Cash 250

9 Oct 31 Accounts receivable 33,100

Fees earned 33,100

10 Oct.31 Utility Expense 1,050

Cash 1050

11 Oct.31 Drawings 2,500

Cash 2,500

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The price of one country currency expressed in another country currency definition

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4 years ago

Armstrong Corporation manufactures bicycle parts. The company currently has a $18,500 inventory of parts that have become obsole

MaRussiya [10]

Explanation:

There are two alternatives

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The inventory parts should be sold for $6,300 as the current inventory parts are not relevant as it is a sunk cost i.e $18,500

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As we can see that the alternative 2 generated higher benefit as compare to the alternative 1 so it would be more beneficial for the company

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3 years ago

For a competitive market, A. a seller can always increase her profit by raising the price of her product. B. a seller often char

PtichkaEL [24]

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Explanation:

A perfectly competitive market has the following characteristics:

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Therefore , if a seller charges more than the going price, buyers will go elsewhere to make their purchases.

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4 years ago

Describe your motivation for becoming a licensed cosmetologist/manicurist. please help

GrogVix [38]

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Read more about cosmetologists/manicurists.

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2 years ago

A manufacturer can produce at most 140 units of a certain product each year. The demand equation for the product is pequalsq squ

Leokris [45]

Answer:

As it can sale up to 140 it should sale 140 units

Explanation:

P = Q^2 - 100Q + 4800

C = 2/3Q^2 -30Q + 15,000Q^-1

Profit per unit P - C = (1/3Q^2 -70Q + 4800 - 15000Q^-1)

Total Profit Profit per unit x Q

1/3Q^3 - 70Q^2 + 4800Q - 15000

As this is a third degree equation the profit scalates therefore the company should sale as much as possibley can to make profit

As it can sale up to 140 it should sale 140 units

Also if we try to detemrinate the point at which Marginal revenue matches Marginal cost:

Revenue

P x Q = (Q^2 - 100Q + 4800) x Q = Q^3 - 100Q^2 + 4800Q

marginal Revenue (slope of the revenue funciton)

3Q^2-200Q+4,800

Cost

C x Q = (2/3Q^2 -30Q + 15,000Q^-1)* Q = 2/3Q^3 -30Q^2 + 15,000

Marginal Cost (slope of the cost function)

2Q^2 - 60Q

Marginal Revenue = Marginal Cost

3Q^2-200Q+4,800 = 2Q^2 - 60Q

Q^2 -140Q + 4800 = 0

When solving with the quadratic formula for the root (profit maximization point we notice the isn't a solution thus It cannot be solved which enhance the previous point that there isn't a profit maximization point in this assignment.

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3 years ago