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Lapatulllka [165]
3 years ago
13

The circumference of a circle is 3π in. What is the area of the circle? ​ 1.5π ​ in² ​ 2.25π ​ in² ​ 6π ​ in² ​ 9π ​ in²

Mathematics
2 answers:
Goryan [66]3 years ago
4 0

Answer:

B. 2.25\pi \text{ inches}^2

Step-by-step explanation:

We have been given that the circumference of a circle is 3\pi inches. We are asked to find the area of the circle.

Since we know that the circumference of a circle is 2\pi r.

\text{Circumference}=2\pi r

Upon substituting the circumference as 3\pi\text{ inches} we will get,

3\pi=2\pi r

Let us divide both sides of our equation by 2\pi.

\frac{3\pi\text{ inches}}{2\pi}=\frac{2\pi r}{2\pi}

\frac{3}{2}\text{ inches}=r

1.5\text{ inches}=r

\text{Area of circle}=\pi r^2

Upon substituting r=1.5 in area of circle formula we will get,

\text{Area of circle}=\pi*(1.5\text{ inches})^2

\text{Area of circle}=\pi*2.25\text{ inches}^2

Therefore, the area of circle will be 2.25\pi \text{ inches}^2 and option B is the correct choice.

dangina [55]3 years ago
3 0
C = 2<span>πr
so
r = C/2</span><span>π
r = 3</span>π/2<span>π
r = 3/2
r = 1.5

A = </span><span>πr^2
A = </span><span>π(1.5)^2
A = 2.25</span><span>π 

answer
</span><span>2.25π ​ in²</span>
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(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
3 years ago
Triangle ABC is translated 4 units down and 6 units right, resulting in triangle A'B'C'.
gogolik [260]

Answer:

The new coordinate of B' will be ( -1, 6)

7 0
3 years ago
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A. 3(x + 2) = 18. B. 3x + 6 = 18 how can we get equation B from equation A? Choose 1 answer
Leto [7]
A-
3x+6=18
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7 0
3 years ago
A recipe uses 100 g of flour, 100 g of sugar and 80 g of butter.
Maslowich

Answer:

600 butter : 2000 flour : 200 sugar : 400 currants = 72 cakes

120 cakes could be made with 1 kg of butter

Step-by-step explanation:

Here, 72 cakes = 6 dozen cakes

( since 12 cake = 1 dozen cake ).

a. First calculate quantity of each ingredient per dozen by dividing each by 1.5 (18/12).

• Butter - 150/1.5 = 100 g per dozen

For 6 dozen :

100g x 6 = 600 g

• Flour - 500/1.5 = 333.33 g per dozen

For 6 dozen :

333.33 g x 6 = 2000 g

• Sugar - 50/1.5 = 33.33 g per dozen

For 6 dozen :

33.33 x 6 = 200 g

• Currants - 100/1.5 = 66.67 g per dozen

For 6 dozen :

66.67 x 6 = 400 g

b. It is given that,

150g butter is required to make = 18 cakes

Then by using unitary method, we get,

1 g of butter is required to make = 18/150 cakes

Since, 1 Kg = 1000 g

Then,

1000 g of butter is required to make = (18/150) × 1000

= 120 cakes

Hence, with 1 kg of butter 120 whole cakes can be made.

Hope this answer helps you :)

Have a great day :)

Mark brainliest

4 0
3 years ago
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Answer:

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<u />

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