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MaRussiya [10]
3 years ago
12

−30=5(x+1) please simplify this for khan academy. org

Mathematics
2 answers:
andrew11 [14]3 years ago
5 0

Answer: x=-7

Step-by-step explanation:

-30=5(x+1)

multiply the brackets

-30=5x+5

take away 5x from both sides of the equation

-30-5x=5

add 30 to both sides

-5x=35

divide both sides by -5

x=-7

brilliants [131]3 years ago
4 0

Answer:

-7 =x

Step-by-step explanation:

−30=5(x+1)

Divide each side by 5

−30/5=5/5 (x+1)

-6 = x+1

Subtract 1 from each side

-6-1 = x+1-1

-7 =x

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C. 18x+9y

Step-by-step explanation:

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You take 16 and -5 and subtract them to get the answer which is 11
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if a person puts 1 cent in a piggy bank in the first day, 2 cents on the second day, 3 cents on the third day, and so on, how mu
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Help me please i reallly need it​
xxMikexx [17]

Answer:

a) A = 64(2s - 1)

b) A = 1,856 cm²

Step-by-step explanation:

Given the side of the frame, 8s, and that the border that frames the picture is 4 on either side = 8:

<h3>a) Find an expression for the area of the frame, in factored form. </h3>

A = area of the square frame

A₁ = Total area (including the picture inside the frame) = (8s)²

A₂ = Area of the picture inside the frame = 4 + 4 = (8s - 8)²

To find the area of the frame, subtract the area of the picture from the total area.

A = A₁ - A₂

A = (8s)² - (8s - 8)²

Perform the necessary exponential operations:

A = 64s²- (64s² - 64s - 64s + 64)

A = 64s²- (64s² - 128s + 64)

A = 64s²- (64s² - 128s + 64)

Distribute -1 into the parenthesis:

A = 64s²- 64s² + 128s - 64

Combine like terms:

A = 0 + 128s - 64

A = 128s - 64

Factor out 64:

A = 64(2s - 1)

The expression for the area of the frame in factored form is: A = 64(2s - 1).

<h3>b) Determine the area of the frame when s = 15cm</h3>

Using the same expression from part A:

A = 64(2s - 1)

Substitute s = 15 into the expression:

A = 64[2(15) - 1]

A = 64(30 - 1)

A = 64(29)

A = 1,856 cm²

Therefore, the area of the frame that has a side of 15 cm is: A = 1,856 cm²

6 0
2 years ago
The percent of working students increased 21.7% to 8.9%, what was the percent prior to increase​
blagie [28]

Answer:

Approximately 7.3%.

Step-by-step explanation:

What is percentage increase?

\displaystyle \text{Percentage Increase} = \frac{\text{Final Value} - \text{Initial Value}}{\text{Initial Value}} \times 100\%.

For this question:

  • \text{Percentage Increase} = 21.7\%,
  • \text{Final Value} = 8.9\% = 0.089, and
  • \text{Initial Value} needs to be found.

Let \text{Initial Value} = x.

\displaystyle \frac{0.089 - x}{x} = 0.217.

Assume that x \ne 0. Multiply both sides of the equation by x:

0.089 - x = 0.217x.

Add x to both sides of the equation:

0.089 = (1 + 0.217)x.

\displaystyle x = \frac{0.089}{1 + 0.217} = 0.0731 \approx 7.3\%.

In other words, the initial percentage is approximately 7.3%.

4 0
3 years ago
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