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scoundrel [369]
4 years ago
11

Can someone help me with these 3

Mathematics
1 answer:
photoshop1234 [79]4 years ago
8 0
24. 244 cm

25. 65 mm

26. 37/80 or 0.4625

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Find the equation of the straight line that passes through the point (1,1/2) and has slope 1/2. Enter the equation in the point-
Nataliya [291]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ \frac{1}{2}}})\quad 
%   (c,d)

\end{array}
\\\quad \\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{2}
\\ \quad \\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values}\\

\end{array}\\
\qquad \uparrow\\
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5 0
3 years ago
A cleaner recommends mixing 1 1/2cup of cleaner for every 12 cups of water. What is the ratio of cleaner to water ?
Eva8 [605]

Answer:

1:8

Explanation:

1.5 (cleaner) to 12 (water)--> simplified is 1:8

5 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
Jaerd made 12 3/4 cups of snack mix for a party. His guest ate 2/3 of the mix. How much snack did his guest eat
77julia77 [94]

Answer:

8 1/2 cups

Step-by-step explanation:

12 3/4 divided by 3= 4 1/4 times 2 = 8 2/4 = 8 1/2

5 0
3 years ago
Read 2 more answers
Please help with this
GalinKa [24]
The answer is 20


Reason: so the W is 4 and the L is 6 so you do 4+4=8 then you do 6+6=12 then you add the two together and get 20
7 0
3 years ago
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