Answer:
The density is equal to the weight divided by the volume:
The paperweight weights 300 grams.
Step-by-step explanation:
The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.
The density is equal to the weight divided by the volume:
We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.
We can use the formula of the density to calculate the weight:
The paperweight weights 300 grams.
Answer:
Step-by-step explanation:
The figures dont have enough letters to explain step by step all the exercises.
Bread 1:
The horizontal lines are parallels so both angles must be the same
2x + 21 = 4x - 17
21 + 17 = 4x - 2x
38 = 2x
x = 19
Bread 2:
Angles sum 180°
3y - 5 + 2y - 25 = 180
5y - 30 = 180
5y = 180 +30
5y = 210
y = 42
Bread 3:
Angle ABC is the same as the other 2, since x = 19
ABC = 2x + 21
ABC = 2 * 19 + 21
ABC = 59
Bread 4:
Angle ABC is the same as 3y - 5, y = 42
ABC = 3y - 5
ABC = 3 * 42 -5
ABC = 121
Bread 5:
Angles must be the same
5x - 14 = 2x + 13
5x - 2x = 13 + 14
3x = 27
x = 9
Bread 6:
Angle ABC = 5x - 14 , x = 9
ABC = 5 * 9 - 14
ABC = 31
If you need to understand why the angles must be the same just comment and I will give you more details
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
(4,-8)
Step-by-step explanation:
from -5 to -1 you would have to count from 1 to 4. and do the same for -8 to -16
Angle 1 = 30°
Angle 2 = 90°
⇒ Angle 3 = 60°
So, it's right triangle. We can set the length of one side and get all other sides.
So, we have 1 triangle. If there are 2 or more triangles with the same data, all the triangles will be congruent because of : <span>Two triangles are </span><span>congruent if </span>"<span>ASA: Two interior angles and the included side in a triangle have the same measure and length, respectively, as those in the other triangle</span><span>.</span>"
