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Taya2010 [7]
3 years ago
8

Which of the following is an example of the law of detachment? A. If an animal is a sparrow, then it flies. If an animal flies,

then it is a bird. An animal is a sparrow. Therefore, the animal is a bird. B. If an animal is a sparrow, then it flies. An animal is not a sparrow. Therefore, the animal doesn’t fly. C. If an animal is a sparrow, then it flies. An animal flies. Therefore, the animal is a sparrow. D. If an animal is a sparrow, then it flies. An animal is a sparrow. Therefore, the animal flies.
Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0
The answer should be A
VladimirAG [237]3 years ago
8 0
A because <span>If an animal is a sparrow, then it flies. If an animal flies, then it is a bird. An animal is a sparrow. Therefore, the animal is a bird.</span>
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Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
How do you solve 3(15.9 - 3.9)<br> Step by step? I need help
N76 [4]

Answer:

36

Step-by-step explanation:

3(15.9 - 3.9)

3 · (15.9 - 3.9)

3(15.9) - 3(3.9)

47.7 - 3(3.9)

47.7 - 11.7

36

5 0
3 years ago
Read 2 more answers
martin is ordering dvds online. each dvd is priced at $8.50. the wedsite also charges a flat fee of $5.00 for shipping and handl
Anon25 [30]
Y=8.50x+5.00
56=y
-56=8.50x+5.00

56=8.50x+5.00
-5.00         -5.00
51=8.50x
÷8.5 ÷8.5

6=x  <u>HE CAN BUY 6 DVDS</u>
7 0
3 years ago
Can somebody please help me?
ElenaW [278]
 <span>for the first part, realize that the hour and minute hands are moving at different rates; in one hour, the minute hands moves all the way around the face of the clock, and thus moves a total of 360 degrees or 2 pi radians; the hour hand moves only 1/12 away around the clock, so covers only 30 degrees or Pi/6 radians. 

Now, the LINEAR distance traveled by the tip of each hand is also determined by the length of the hand. In the case of the minute hand, it sweeps out a circle of radius 10 cm, so traces out a circle of radius 10 cm. Since the circumference of a circle is 2*pi*r, the minute hand (remember it made one complete cycle) covers a distance of 2*pi*10cm=20 Pi cm 

The hour hand covers only 1/12 a circle, but that circle is only 6 cm in radius, so the distance traveled by the tip of the minute hand is: 

1/12 *[2 *pi*r]=1/12*[12*pi]=pi 

so the difference is 19pi 

for the last part, you should draw a diagram of the two hands, the minute hand is 10 cm in length, the hour hand is 6 cm in length, and they are 30 degrees apart...from that drawing, see if you can figure out the remaining leg of the triangle you can form from them 

good luck</span><span>
</span>
8 0
3 years ago
Problem page the length of a rectangle is four times its width. if the perimeter of the rectangle is 70 cm , find its area.
agasfer [191]
So we can call the width of the rectangle x.
So then the length would be 4x.
The perimeter would then be 10x.
Since the perimeter is 70, we can say 70 = 10x.
And then simplify that to 7 = x.
So the length of a rectangle would be 28 cm, and the width would be 7.
So to find the area, just multiply length by width.
28*7 = 196 square cm
So the rectangle's area is 196 square cm.

I hope I helped!
5 0
3 years ago
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