4. In the quadratic function y = 232 + ba + c, the affects the width of the parabola.

Please help Ill give brainy pleas help please -

mars1129 [50]

The answer to this is a=3

4 0

2 years ago

Solve for x 1 7 1 2 х Your answer

ki77a [65]

Answer:

x = 4

Step-by-step explanation:

3x -5 = -2 + 9

-2 + 9 = 7 so now its 3x - 5 = 7

add 5 to the -5 so it cancels itself out. then add the 5 to 7 so it become 12. the you have 3x = 12

divide 12 ÷ 3 = 4

x = 4

8 0

3 years ago

Read 2 more answers

If a gardener fences in the total rectangular area shown in the illustration instead of just the square area, he will need twice

Norma-Jean [14]

Answer:

He needs 5x+56 ft

Step-by-step explanation:

To find how much of fencing he needs , we find the perimeter of the given figure

All sides are equal in a square

To find perimeter of the square we add all the sides

4 sides we have for the square

one side is x, so perimeter of square = x+x+x+x= 4x

Now we find perimeter of rectangle

Opposite sides of rectangle are equal

Here for rectangle we consider only three sides

because fourth side is common for rectangle and square

So perimeter of the rectangle (with 3 sides) = 28 +x+ 28 = 56+x

Total fencing = perimeter of square + perimeter of rectangle

4x + 56 + x= 5x+56

5 0

3 years ago

Which number is greatest? 2.89 times 10 Superscript negative 8 1.997 times 10 Superscript 2 8.9 times 10 Superscript negative 6

love history [14]

<h3> The greatest number is $1.997 \times 10^2$ </h3>

Solution:

Given that the numbers are:

$2.89 \times 10^{-8}\\\\1.997 \times 10^2\\\\8.9 \times 10^{-6}\\\\5 \times 10^{-6}$

We have to find the number that is greatest

Convert the numbers to decimal

$2.89 \times 10^{-8} = 2.89 \times \frac{1}{10^8} =0.0000000289$

$1.997 \times 10^2 = 199.7$

$8.9\times 10^{-6}=8.9\times \frac{1}{10^6}=0.0000089$

$5\times 10^{-6}=5\times \frac{1}{10^6}=0.000005$

We can clearly see that, 199.7 is greatest number

Thus the greatest number is $1.997 \times 10^2$

3 0

4 years ago

Read 2 more answers

Use the information to answer the questions.

Anna71 [15]

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) $b^2=a^2+c^2-2(a)(c)cos(B)$

Part 3) $b=11.6\ in$

Step-by-step explanation:

we have

In the triangle ABC

$a=11\ in\\c=9\ in\\B=70^o$

Part 1) Which information about the triangle is given?

In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)

see the attached figure to better understand the problem

Part 2) Which formula can you use ti find b?

I can use the law of cosines

$b^2=a^2+c^2-2(a)(c)cos(B)$

we have

$a=11\ in\\c=9\ in\\B=70^o$

substitute the given values

$b^2=11^2+9^2-2(11)(9)cos(70^o)$

$b^2=202-67.72$

$b=11.59\ in$

Part 3) What is b, rounded to the nearest tenth?

Remember that

To Round a number

a) Decide which is the last digit to keep

b) Leave it the same if the next digit is less than $5$ (this is called rounding down)

c) But increase it by $1$ if the next digit is $5$ or more (this is called rounding up)

In this problem we have

$11.59\ in$

We want to keep the digit $5$

The next digit is $9$ which is 5 or more, so increase the "5" by 1 to "6"

therefore

$b=11.6\ in$

4 0

3 years ago