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xeze [42]
2 years ago
6

The total operating cost for the truck is $400 000 per year. The percentage breakdown of this total amount was: 40%: Fixed costs

(insurance, registration, wages) 30%: Fuel 20%: Finance 10%: Maintenance (service, repairs, tyres) Suppose the fuel price increases from $1.50 to $1.60 per litre. How much does this add to the total operating cost per year?
Mathematics
1 answer:
Viktor [21]2 years ago
7 0
To find this, you have to find the specific cost of each service.
40% fixed costs: 400000 x 0.4 = 160000$
30% fuel: 400000 x 0.3 = 120000$
20% finance: 400000 x 0.2 = 80000$
and 10% maintenance: 400000 x 0.1 = 40000$
So the price was originally $1.50 (for fuel). This means that 120000$ was spent on fuel. Doing the math, it's 120000/1.50 = <span>80000 liters of fuel. So at the new price, the cost of all 80k liters would be 80000 x 1.60 = 128000. That's a 8000 increase in price, so the total cost is now $408000.</span>
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Answer:

P = 100

Area = 625

Step-by-step explanation:

Area = s^2

sqrt(area) =  sqrt(s^2)

area = 25*25

sqrt(25*25) = sqrt(s^2)

s = 25

P = 4*s

P = 4 * 25

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icang [17]

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(4, -3)

Step-by-step explanation:

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e-lub [12.9K]

Answer:

The equation in the standard form is

y+2x=5

Step-by-step explanation:

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Finding the slope between (6, -7) and (4, -3)

\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)

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m=\frac{-3-\left(-7\right)}{4-6}

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As the point-slope form is defined as

y-y_1=m\left(x-x_1\right)

substituting the values m = -2 and the point (6, -7)

y-y_1=m\left(x-x_1\right)

y-\left(-7\right)=-2\left(x-6\right)

Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

converting the equation in standard form

y-\left(-7\right)=-2\left(x-6\right)

y+7=-2\left(x-6\right)

subtract 7 from both sides

y+7-7=-2\left(x-6\right)-7

y=-2x+5

y+2x=5

Therefore, the equation in the standard form is

y+2x=5

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The H.C.F of 2,3 and 6
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1   is the hcf of 2,3,6

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