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SVEN [57.7K]
3 years ago
11

Help me on number 1 please

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0
The answer is B because 140-110= 30

andreev551 [17]3 years ago
3 0
Sunday140 - Thursday 110 =
B.30
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3 years ago
Several years​ ago, 43​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
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<h2><u>Answer with explanation</u>:</h2>

Let p be the population proportion of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Set of hypothesis :

H_0: p=0.43\\\\ H_a:p\neq0.43

Confidence interval for population proportion is given by :-

\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}} , where

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\hat{p}= sample proportion

and z_c is the two-tailed z-value for confidence level (c).

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Sample size of parents : n= 1085

Number of parents indicated that they were satisfied= 466

Sample proportion :  \hat{p}=\dfrac{466}{1085}\approx0.429

Critical value for 90​% confidence interval : z_c=1.645  ( by z-value table)

Now, the  90​% confidence interval :

0.429\pm (1.645)\sqrt{\dfrac{0.429(1-0.429)}{1085}}\\\\=0.429\pm 0.0247\\\\=(0.429-0.0247,\ 0.429+0.0247)\\\\=(0.4043,\ 0.4537)

Thus , the 90​% confidence interval: (0.4043, 0.4537).

Since 0.43 lies in 90​% confidence interval , it means we do not  have enough evidence to reject the null hypothesis .

i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.

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Answer:

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