Answer with explanation:

Average Height of tallest Building in San Francisco

Average Height of tallest Building in Los Angeles

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers

Mean absolute deviation=23.12
Answer:
h = 40°
Step-by-step explanation:
These 2 angles are congruent due to the Corresponding Angles Theorem.
4p+9-7p+2=
group like terms
4p-7p+9+2
addd like terms
-3p+11
that is simplified form
Answer:

Step-by-step explanation:
We have given the equation y = 6 sin (x)
On differentiating both side 
As it passes through the point 
So 
Now the unit vector is parallel to the tangent so m will be 5.196
This passes through the point 
So unit vector will be 


cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.