What is 123.45 rounded to the nearest tenths place

Mathematics

2 answers:

natali 33 [55]3 years ago

8 0

Answer:120.00

Step-by-step explanation:

The number after the tenth digit is less than 5 so we round down

Artist 52 [7]3 years ago

3 0

Answer:

120

Step-by-step explanation:

You might be interested in

A potato chip manufacturer produces bags of potato chips that are supposed to have a net weight of 326 grams. Because the chips

marusya05 [52]

When we take data at work, we always do it over a period of time. To me, just one sample set does not show enough data to come to that conclusion. Also it is one batch of bags. I think you would need to have an average of data from different batches & samples to prove your data is accurate and support your claim.

6 0

2 years ago

(- 6x + 7) + (2x - 6) = - 4x + 1

inna [77]

Answer:

Step-by-step explanation:

-4x + 1 = -4x + 1

1 = 1

infinitely many solutions

7 0

3 years ago

The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func

alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

$h(t)=-16t^2 + 96t$

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

$To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq 0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq 0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)$

$Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq 0\\-112 \geq 0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq 0\\80 \geq 0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq 0\\-112 \geq 0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution$