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guajiro [1.7K]
3 years ago
11

Which conjunction is true?

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0
A is incorrect because isosceles cannot have right angles and right triangles cannot be isosceles. A square is not a rhombus, so B is incorrect. And yes, a kite is a rhombus and a parallelogram. You didn't finish C, but right triangles cannot be isosceles, but right triangles can have two acute angles 
Alik [6]3 years ago
5 0

Answer explanation:

1 . The given conjunction is : An isosceles triangle has two congruent sides and a right angle.

It can be or cannot be true.  An isosceles triangle can have one right angle and two other angles equal to each other , each being 45°.But it is a special isosceles triangle called ,isosceles Right triangle.

So, this conjunction is not  completely true.

→2. The Given conjunction is : A square is a: Rhombus and a rectangle.

Yes , this conjunction is true, Because ,Square Satisfies all the properties of Rhombus and Rectangle.

The Properties of Square are

1. All sides equal and each interior angle equal to 90°.

2. Opposite sides are parallel.

3. Diagonals bisect each other at right angles.

Properties of Rhombus

1. All sides are equal.

2. Opposite sides are parallel.

3. Diagonals bisect each other at right angles.

Properties of Rectangle

1.Opposite sides are equal.

2. Diagonals bisect each other.

3.Opposite sides are parallel.

4. Each interior angle measures 90°.

⇒Square Satisfies all the properties of Square and rhombus.

Yes, this Conjunction is true.

→→3rd and 4th Conjunction is incorrect, which is→ A kite is rhombus and a parallelogram,is incorrect because kite has,two pair of adjacent sides which are equal, but a rhombus has all sides  equal,whereas parallelogram has opposite sides equal.

→ A right triangle ,is isosceles and has two acute angles.→A right  triangle is isosceles,is a special case, otherwise it has two acute angles and one right angle is true statement,but it is isosceles is not true.

Option B, is a true Conjunction:→ A square is a b.rhombus and a rectangle.

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sweet [91]

(a) i. See comment...

(a) ii. We have

\vec p = 6\,\vec\imath - 3\,\vec\jmath + 9\,\vec k

and

\vec q = 3\,\vec\imath - 6\,\vec\jmath - 3\,\vec k

(b) We can parameterize the line segment from P to Q by the vector function

\vec r(t) = (1-t) \vec p + t \vec q = (6-3t) \, \vec\imath + (-3-3t) \,\vec\jmath + (9-6t) \,\vec k

with 0\le t\le1. The point R is located 1/3 of the way along this line segment, i.e. at t=\frac13, so its position vector is

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2 years ago
Find two numbers if their sum is 91 and the ratio is 6:7.
sammy [17]

Answer:

42:49

Step-by-step explanation:

6x + 7x = 91

13x = 91

x = 7

6 x 7 = 42

7 x 7 = 49

then 42:49

5 0
4 years ago
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A puppy is on sale at a pet store for ​$432​, marked down 10​% from an original selling price of ​$480. If the markup from cost
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432 x 0.1 = 43.2
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4 0
3 years ago
If F(x) = 3x + 10x and g(x) = 5x - 3, find (f+g)(x)
Ugo [173]
(f+g)(x) represents the sum of the two functions f(x) and g(x).

Arrange these functions vertically and add up like terms:

<span>   f(x) = 3x + 10
</span><span>+g(x) = 5x - 3
-----------------------
(f+g)(x) = 8x + 7

Please note:  You've typed in "</span><span>F(x) = 3x + 10x and g(x) = 5x - 3."
I doubt that F(x) actually equals 3x + 10x.  Please ensure that you have copied down the original problem correctly.  Come back once you've done that, so that we can finish this problem solution.</span>
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3 years ago
The population of the world grows exponentially at a rate of 1.1% per year.
natima [27]

Answer:

4

Step-by-step explanation:

Every year, the world grows by 1.1%. Converting to a decimal, we can divide by 100 to get 1.1% = 0.011. This means that the world grows by 0.011 exponentially each year. To put this into an expression, we can add 1 to our percentage to get 1.011. This represents 1 = 100% (the original population) and the growth of 1.1% = 0.011. We multiply the rate including the growth by the population to get the population after one year. After the first year, we have

population * 1.011 as the new population after one year. We do that for every year, so the second year's population is population*(1.011)*(1.011) and so on. If x represents the amount of years, then the population can be represented as

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Therefore, to get from 7 billion to 7.31 billion, we have

7 billion * 1.011ˣ = 7.31 billion

divide both sides by 7 billion to relatively isolate the x

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Another way of writing this is

log (base 1.011) (7.31/7) = x

≈ 3.96

Rounding to the nearest whole number, we get 4 as our answer

7 0
3 years ago
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