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lawyer [7]
3 years ago
10

Simplify 2x2a^2 x2a^2

Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Step-by-step explanation:

> 2×2a²×2a²

8a⁴

> 36a³×1/4a²

9a³×1/a²

9a

> 2⁶

> 5²m²

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If cos x=8/17, and 270° &lt; x &lt; 360°<br> what is cos(2x)?
svp [43]

Answer:  \bold{-\dfrac{161}{289}}

<u>Step-by-step explanation:</u>

Given: cos x = \dfrac{8}{17}, x is in Quadrant 4

Use Pythagorean Theorem to find sin x:

8² + y² = 17²    

      y² = 17² - 8²

      y² = 289 - 64

      y² = 225

      y = 15

→    sin x = -\dfrac{15}{17}

Use the double angle formula to find cos (2x):

cos (2x) = cos^2 x - sin^2 x\\\\.\qquad=\bigg(\dfrac{8}{17}\bigg)^2-\bigg(-\dfrac{15}{17}\bigg)^2\\\\\\.\qquad=\dfrac{64}{289}-\dfrac{225}{289}\\\\\\.\qquad=-\dfrac{161}{289}

             

8 0
3 years ago
Read 2 more answers
you roll a blue number cube and a green number cube. find P ( a number less than 2 on the blue vube and odd number on the green
Kruka [31]

ON the blue cube there are 4 numbers greater than 2 and on the blue cube, 3 of the numbers are odd. As soon as BOTH outcomes have to happen (AND), you multiply the probabilities.

<span><span>4/6</span>×<span>3/6</span>=<span><span>1/3</span></span></span>

6 0
3 years ago
Read 2 more answers
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
Anyone? /: please help!!
NeTakaya
The answer is Side RQ corresponds to side QQ'. 100% sure and please feel free to ask more.
5 0
3 years ago
Help me please due in 20 minutes
Kamila [148]

Answer:

y=4

Step-by-step explanation:

4 0
3 years ago
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