Using the Theorem of Pythagoras (a² + b² = c²)
Put in the values:
12² + 12² = 28²
Is it correct? (solve)
Nope! Because 12² + 12² = 288, and the square root of 288 is about 17, not 28.
The answer is no, 12cm, 12cm, 28cm cannot form a triangle.
Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
D.y = -3/5x - 2
mggfffffffffffffffffffffffffffffffffffffffff
X={6,-10} that is the answer
It would be...
(18 +28) divided by two
then take that and multiply it by the height - 5
the 6 in this equation doesn't matter because it is not the height of the shape
We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56
