3 years ago

4(k-3) = -12 + 4k

Mathematics

1 answer:

denis23 [38]3 years ago

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66 is the answer to the question

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luda_lava [24]

Answer:

The required formula is:

$\ a_{n}=a_{1}+(n-1)d$

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

$a_1=4$

$a_2=7$

$a_3=10$

Finding the common difference d

$d=a_3-a_2=10-7=3$

$d=a_2-a_1=7-4=3$

As the common difference 'd' is same, it means the sequence is in arithmetic.

If the initial term of an arithmetic progression is $a_{1}$ and the common difference of successive members is d, then the nth term of the sequence $(a_n)$ is given by:

$\ a_{n}=a_{1}+(n-1)d$

Therefore, the required formula is:

$\ a_{n}=a_{1}+(n-1)d$

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Answer:

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Step-by-step explanation:

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Answer:

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Explanation:

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