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kumpel [21]
3 years ago
6

4(k-3) = -12 + 4k

Mathematics
1 answer:
denis23 [38]3 years ago
7 0
66 is the answer to the question
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HELP!!! WILL GIVE BRAINLIEST!!!! 40 POINTS!!!!!! The agriculture department of a university works with individuals wanting to bu
alexgriva [62]

Answer:

Should be something along the lines of:

3,450 = 326x - 310

Step-by-step explanation:

First, let's start with the number of years. Assume the number of years is x. 3262 greenhouses amounts to about 326 greehouses/year. The other number was the existing greenhouses, but we want just how many greenhouses that were built, per the subtraction sign.

Hope this helps!! : )

Sorry if I am wrong, haven't done equations in a while.

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3 years ago
8. Use mental math to multiply. a) 235 times 0.1, b) 235 times 0.01, c) 876 times 0.01, d) 876 times 0.001,
lys-0071 [83]

Step-by-step explanation:

235•0.1=23.5

235•0.01=2.35

876•0.01=87.6

876•0.001=8.76

7 0
3 years ago
Expand the logarithmic expression. I will award brainliest.
Natasha_Volkova [10]
\bf \textit{logarithm of factors}\\\\
log_a(xy)\implies log_a(x)+log_a(y)
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\textit{Logarithm of rationals}\\\\
log_a\left(  \frac{x}{y}\right)\implies log_a(x)-log_a(y)
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\textit{Logarithm of exponentials}\\\\
log_a\left( x^  b \right)\implies   b\cdot  log_a(x)\\\\
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log_3\left( \cfrac{2r^5}{y^8} \right)\implies log_3(2r^5)-log(y^8)
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\boxed{log_3(2)+log_3(r^5)}-log_3(y^8)\implies log_3(2)+5log_3(r)-8log_3(y)
8 0
3 years ago
Which equation can be used to find A, the area of the parallelogram shown?
Korvikt [17]

Answer:

A = 6 x 7

Step-by-step explanation:

To find the area of a parallelogram we use the equation of Area = base x height. In this case since the base is 6 and the height is 7, we plus in these numbers for the variables (b x h) to get the area.

5 0
3 years ago
The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
3 years ago
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