Step-by-step explanation:
General line equation: y = mx + c.
2y + 3x = 5
2y = -3x + 5
y = -1.5x + 2.5
Hence m = -1.5 and c = 2.5.
1) 462/11= 42
42x7=294
2) 9.38/7= $1.34
3) 6/11= 0.54545454545455
4) 1/4= 0.25
2/9= 0.22222222222
3/10= 0.30
2/1= 2.00
1/5= 0.20
least to greatest- 1/5, 2/9, 1/4, 3/10, 2/1
5) 9/15= 0.6 > 60%
to turn into a percent, move 2 decimal places!
6) 10/4= 2.5
2.5x18= 45
7) 2/3= 0.66666666666
0.66666666666x7= 4.66666666667
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx =
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx =
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Answer:
The school is closest
Step-by-step explanation:
Plot the point of the library and measure the distance from the library to each location.