For this case we have that by definition of trigonometric relations of a rectangular triangle that, the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle.
That is to say:
We clear the length of the leg:
Answer:
There is no picture, but here are the directions to finding the surface area.
1. Find the area of the square(A = bh) and remember that the base and the height will be the same on a square).
2. Find the area of one of the triangular faces (A = 1/2bh), where the base would also be the length of the side of the square and the height the lateral height of the triangular face).
3. Multiply your answer from 2 by 4 because there are 4 of these.
4. Add you answers for #3 and #1 to get the total surface area.
Answer:
62 degrees
Step-by-step explanation:
If two angles are complementary, it means that their sum is 90degrees
Hence if m<a and m<b are complementary, then;
m<a + m<b = 90
Given
m<a = 28degrees
Required
m<b
Substitute into the formula as shown;
28 + m<b = 90
m<b = 90 - 28
m<b = 62degrees
Hence the measure of angle b is 62 degrees
Answer:
B) >
Step-by-step explanation:
We can convert the fractions into decimals to see which is greater.
3/5 = 0.6
5/10 = 0.5
From this, we can see that 3/5 is greater than 5/10, so the sign is >.
hope this helps :)
Answer:
Step-by-step explanation:
The question presumes you have access to a computer algebra system. The one I have access to provided the output in the attachment. The list at the bottom is the list of the first four derivatives of f(x).
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The derivatives alternate signs, so (-1)^k will be a factor.
The numerators start at 17 and increase by increasing factors: 2, 3, 4, indicating k! will be a factor.
The denominators have a degree that is k+1.
Putting these observations together, we can write an expression for the k-th derivative of f(x):