Answer:
96π or 301.59 in³
Step-by-step explanation:
V(cone) = 1/3πr²h
= 1/3·π·6²·8
= 96π or 301.59
So let f(x) = x^(2/3)
<span>Then let f'(x) = 2/3 x^(-1/3) = 2 / (3x^(1/3)) </span>
<span>When x = 8, </span>
<span>f(8) = 8^(2/3) = 4 </span>
<span>f'(8) = 2 / (3*8^(1/3)) = 1/3 </span>
<span>So near x = 8, the linear approximation is </span>
<span>f(x) ≈ f(8) + f'(8) (x - 8) </span>
<span>f(x) ≈ 4 + 1/3 (x - 8) </span>
<span>So the linear approximation for x = 8.03 is... </span>
<span>f(8.03) ≈ 4 + 1/3 (8.03 - 8) </span>
<span>f(8.03) ≈ 4 + 1/3 (0.03) </span>
<span>f(8.03) ≈ 4.01 </span>
<span>8.03^(2/3) ≈ 4.01 </span>
Answer:
12c square meters
Step-by-step explanation:
We know that
Area of a rectangle = length (L)× width(w)
Here it is given that length ,and width of the rectangle is 6c meters and 2 meters respectively.
Therefore, required area of the rectangle = 6c × 2 = 12c square meters.
Answer:
Step-by-step explanation:
y = -4x + 6.....switch x and y and solve for y
x = -4y + 6 ....subtract 6 from both sides
x - 6 = -4y....divide by -4 on both sides
(x - 6) / -4 = y or y = -1/4x + 3/2 <====
55.15 (t) 55.2 (t) 54.34 (t) 52.08 =216.95
