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olga nikolaevna [1]
3 years ago
8

GIVING THANKS AND BRAINLIEST FOR BEST ANSWER <3 ::::::::

Mathematics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

B

Step-by-step explanation:

look closely at the graph pretend the first side is looking through a mirror.

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(the
sleet_krkn [62]

at x = 0, y = 100, y-intercept

meaning at 0 years, at the very beginning of functioning, the satellite had 100 units of power.

at y = 0, x = 10, x-intercept

meaning, at year 10, the satellite had 0 units of power, already out of power.

4 0
2 years ago
Solve the equation. dy dx = ay + b cy + d , where a, b, c, and d are constants. (assume a ≠ 0 and ay + b ≠ 0.)
Reil [10]

 

It solves it in x. the solution for y includes heavy use of the product log function.

dy/dx                                = ay + b/cy +d

(cy +d/ ay + b) dy            = dx

∫ (cy +d/ ay + b) dy          = x (t) + C

 

Into solving the integral, integration by parts followed by u substitution and another integration by parts.

 

∫ (cy +d/ ay + b) dy

u            = cy + d dv          = dy/ay + b

du          = c dy v               = ln I ay + b l / a

 

Then, use u substitution for the new integral

 

u            = ay + b

du          = a dy

∫ ln l ay + b I dy                = ∫ ln IuI /a du    = 1/a ∫ ln luI du

 

Integrating the natural log includes thus far another integration by parts

r             = ln IuI ds            = du

dr          = du / u (s)           = du

∫ ln IuI / du                         = u ln IuI - ∫ du   = u ln IuI - ∫ a dy                                                                                   = (ay + b) ln Iay +bl – ay

 

The original integral of expression

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a² [(ay+b) ln lay+bl – ay]

Then simplify

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a²[(ay+b) ln lay+bl – ay]

                                           = a (cy + d)/a² ln lay+bl – c (ay+b)/ a²ln lay+bl +                                                               c/a² ay

                                           = cay + ad – cay – cb/ a² ln lay+bl + cay/a²

                                           = ad – cb/a²ln lay+bl + cy/a

 The final answer will be

x(t) + C                               = ad – cb/a² ln lay+bl + cy/a

x(t)                                     = ad – cb/a² ln lay+bl + cy/a + k

 

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3 0
3 years ago
How to solve quadratic inequalities.
Digiron [165]

Find all the zeros of the polynomial, and arrange the zeros in increasing order. ...

Plot those numbers on the number line as open or closed points based upon the original inequality symbol.

Choose a test value in each interval to see if the interval satisfies the inequality or not.

6 0
2 years ago
Which expression is equivalent to ? Assume
gladu [14]

[(2x³y⁴)² × 2x]½

(2x³y⁴)½ ×(2x)½

2x³y⁴(2x)½

3 0
2 years ago
HELP!!!!!!!!!!!
liraira [26]
<span>A.The distributions are somewhat similar.

B.The means-to-MAD ratio is 4.

C.The distributions are different.

D.The means-to-MAD ratio is 3.

To get your answer </span>add all them together divide by 8.1 then multiply it to the second power.
8 0
3 years ago
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