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3 years ago

Thanks for your help!

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Answer:

6.3 ft to the nearest tenth.

Step-by-step explanation:

The length of the ladder is 11 ft, the bottom of the ladder is 9 ft from the side of the house.

The height of the house can be calculated using Pythagoras Theorem.

$h^2+9^2=11^2$

This implies that;

$h^2+81=121$

Group similar terms;

$h^2=121-81$

$h^2=40$

Take positive square root of both sides;

$h=\sqrt{40}$

$h=2\sqrt{10}$

$h\approx6.3$ to the nearest tenth

yan [13]3 years ago

3 0

a and b are the two leg sides

c is the longest side.

a^2+b^2=c^2

a=x

b=9

c=11

a=c-b

11 squared is 121

9 squared is 81

121-81=40

The square root of 40, rounded to the nearest hundredth, is 6.32

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2 years ago

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3 years ago

Read 2 more answers

Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

Blizzard [7]

Answer:

Probability is: $\frac{\textbf{13}}{\textbf{51}}$

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$