Question

Thanks for your help!

Answer 1

Answer:

6.3 ft to the nearest tenth.

Step-by-step explanation:

The length of the ladder is 11 ft, the bottom of the ladder is 9 ft from the side of the house.

The height of the house can be calculated using Pythagoras Theorem.

$h^2+9^2=11^2$

This implies that;

$h^2+81=121$

Group similar terms;

$h^2=121-81$

$h^2=40$

Take positive square root of both sides;

$h=\sqrt{40}$

$h=2\sqrt{10}$

$h\approx6.3$ to the nearest tenth

Answer 2

a and b are the two leg sides

c is the longest side.

a^2+b^2=c^2

a=x

b=9

c=11

a=c-b

11 squared is 121

9 squared is 81

121-81=40

The square root of 40, rounded to the nearest hundredth, is 6.32