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3 years ago

6 grade math help me pls

Mathematics

1 answer:

Xelga [282]3 years ago

4 0

Answer:

Median

Step-by-step explanation:

It is symmetric so you have a much easier way to find the middle numbers.

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The gestation period of humans (266 days) is___ percent longer than the gestation period of pigs(115 days).

bija089 [108]

If we take 115 to be the 100%, how much is 266 off of it then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
115&100\\
266&p
\end{array}\implies \cfrac{115}{266}=\cfrac{100}{p}\implies p=\cfrac{266\cdot 100}{115}
\\\\\\
p\approx 231.3$

so 266 is about 231% of 115, which is 131% more than 115.

5 0

3 years ago

Which expression is equivalent to

yKpoI14uk [10]

Answer:

option D is the correct answer

hope it helps you

make me brainliest if u are satisfied with this answer

3 0

2 years ago

Read 2 more answers

I would like to have some help please! ❤ thank youu I need help on the 2 question that is "write three expressions containing ex

Vesna [10]

Answer:

Below

Step-by-step explanation:

Notice that 81 = 9 * 9

So here is the first expression:

● 9^2

9 is 3^2 so 9^2 is 3^4

That's another expression

● 3^4

81 = 9*9 = 3*3*3*3 = 3^3 *3

That's another expression

● 3*3^3

You can keep manipulating the product and create many expressions like:

● 3^2 * 3^2

● 9 * 3^2

6 0

3 years ago

Read 2 more answers

Factor 35y+40z please help.

dedylja [7]

Answer:

i judt want points

Step-by-step explanation:

8 0

3 years ago

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Out of 300 people sampled, 237 preferred Candidate A. Based on this, estimate what proportion of the voting population ( π ) pre

Ronch [10]

Answer:

And the 95% confidence interval would be given (0.744;0.836).

$0.744 \leq \pi \leq 0.836$

Step-by-step explanation:

1) Data given and notation

n=300 represent the random sample taken

X=237 represent the people who prefers the Candidate A

$\hat p=\frac{237}{300}=0.79$ estimated proportion of people who prefers the Candidate A

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Confidence =95% or 0.95

p= population proportion of people who prefers the Candidate A

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

2) Calculating the interval for the proportion

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.79 - 1.96 \sqrt{\frac{0.79(1-0.79)}{300}}=0.744$

$0.79 + 1.96 \sqrt{\frac{0.79(1-0.79)}{300}}=0.836$

And the 95% confidence interval would be given (0.744;0.836).

We are confident that about 74.4% to 83.6% of people prefers Candidate A

5 0

3 years ago