What is the value of A when we rewrite (1/7)^x-2 - (1/7) ^x as A x (1/7)^x

Mathematics

2 answers:

wlad13 [49]3 years ago

8 0

Answer:

Step-by-step explanation:

Khan Academy

vitfil [10]3 years ago

3 0

Answer:

i think its 330

Step-by-step explanation:

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Please answer I need this answer fast please

Fiesta28 [93]

its just a basic logarithmic law.

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3 years ago

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Một khối kim loại có thể tích 3,2cm3 và cân nặng 22,4g. Hỏi một khối kim loại cùng chất có thể tích là 4,5cm3 cân nặng bao nhiêu

Ymorist [56]

Answer:

Một cm3 của khối kim loại đó cân nặng số gam là:

22,4:3,2=7(g)

Một khối kim loại cùng chất có thể tích là 4,5cm3 cân nặng số gam là:

7x4,5=31,5(g)

Step-by-step explanation:

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3 years ago

You were testing orange juice recipes it’s recipe calls for orange juice concentrate and water mix one has 4 cups of concentrate

Sav [38]

Answer:

First mixed is the most orangey.

Step-by-step explanation:

First:

$Orange\ juice\ concentrate=4\ cups\\\\Water=6\ cups\\\\Tota\ content=4+6=10\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{4}{10}\times 100=40\%$

Second:

$Orange\ juice\ concentrate=1\ cups\\\\Water=3\ cups\\\\Tota\ content=1+3=4\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{1}{4}\times 100=25\%$

Third:

$Orange\ juice\ concentrate=2\ cups\\\\Water=4\ cups\\\\Tota\ content=2+4=6\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{2}{6}\times 100=33.33\%$