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Anvisha [2.4K]
3 years ago
10

Points A, B, and C are plotted on the unit circle.

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

where is the circle?

Step-by-step explanation:

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Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
i ran 3hrs and 2 mins to run 26 miles if i ran at the same rate for the whole race how many minutes did it take to run each mile
oksian1 [2.3K]
7 minutes per mile.
8.57 miles per hour
8 0
3 years ago
Which terms and 45p^4q have a GCF of 9p^3?
vredina [299]

Answer:

The answer is 18p^3r and 63p^3

Step-by-step explanation:

G.C.F of 18p^3 r and  45p^4q is = 9p^3

18p^3r = 2*3*3*p*p*p*r

45p^4q = 3*3*5*p*p*p*q

Thus the G.C.F is 3*3*p*p*p = 9p^3

G.C.F of  63p^3 and  45p^4q is = 9p^3

63p^3 = 3*3*7*p*p*p

45p^4q = 3*3*5*p*p*p*q

Thus the G.C.F is 3*3*p*p*p = 9p^3

Therefore the answer is 18p^3r and 63p^3....

7 0
3 years ago
Richard’s checking account balance was $57.34 at the beginning of the week. During the week, he recorded the transactions below.
Tomtit [17]

Answer:

US$ 132.45

Step-by-step explanation:

See attachment for the missing table.

Given:

Richard’s checking account balance at the beginning of the week = $57.34

<u>Richard’s account balance at the end of the week from the given table:</u>

Deposits of the week = US$ 163.75

Expenses of the week = Groceries + Credit card bill + Gas

Expenses of the week = 25.37 + 50 + 13.27

Expenses of the week = US$ 88.64

Richard’s account balance at the end of the week = Richard’s checking account balance at the beginning of the week + Deposits of the week - Expenses of the week

Replacing with the real values:

Richard’s account balance at the end of the week = 57.34 + 163.75 - 88.64

                                                                                    =US$ 132.4

7 0
3 years ago
Read 2 more answers
Question 3 (open to see pic)
melamori03 [73]
The points (1,-2) and (4,16) are not in the line but the point (-3,-18) is on the line. (Work is shown in the image)

8 0
3 years ago
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