$\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ H(5,\ 13)\ \text{and}\ K(7,\ 5).\ \text{Substitute:}\\\\x=\dfrac{5+7}{2}=\dfrac{12}{2}=6\\\\y=\dfrac{13+5}{2}=\dfrac{18}{2}=9\\\\Answer:\ \boxed{(6,\ 9)}$

5 0

3 years ago

Use the graph to determine the vertex point of the quadratic function. Is the vertex a

Feliz [49]

Answer:

B) Vertex (1,2), maximum

Step-by-step explanation:

First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.

The maximum is the point that has the greatest y value. We can see that the greatest y value is at $y=2$ . Going down two units from that spot, we can see that the x value is at $x=1$ . We can plug those into the vertex form, $(x,y)$ . By plugging in we get the point $(1,2)$ .

5 0

3 years ago