All categories

4 years ago

Find the slope between (0,3) and (6,2)

2 answers:

8 0

If u do the formula m=y^2-y^1/x^2-x^1 then u have 3-2/6-0 and that simplifies to 1/6 and that is your answer

answer: 1/6

e-lub [12.9K]4 years ago

5 0

The slope between $(x_1,y_1)$ and $(x_2,y_2$ is $\frac{y_2-y_1}{x_2-x_1}$

so slope between (0,3) and (6,3) is $\frac{2-3}{6-0}=\frac{-1}{6}$

da slope is -1/6

You might be interested in

How many hours is from 8am to 12pm

Ipatiy [6.2K]

I think it's 4 hours

7 0

3 years ago

Read 2 more answers

I need to double check a answer. For measure 1 and 3 I got 117, is that right? But for measure 2 I got 63 which is wrong but I h

cupoosta [38]

Answer:

All are 63

Step-by-step explanation:

m∠1 = 180 - 117 = 63 (linear pair)

m∠2 = 63 (alternate interior angle with ∠1)

m∠3 = m∠1 = 63 (isosceles triangle property)

Hope it helps :)

Please mark my answer as the brainliest

3 0

3 years ago

If line n bisects segment CE, find the positive value of x. A.6 B.10 C.15 D.9

givi [52]

9514 1404 393

Answer:

D. 9

Step-by-step explanation:

The segment lengths are equal, so ...

x^2 = 90-x

x^2 +x -90 = 0 . . . . . . add x-90 to put in standard form

(x +10)(x -9) = 0 . . . . . factor

The solutions are the values of x that make the factors zero: -10, 9.

The positive value of x is 9.

8 0

3 years ago

Read 2 more answers

Every year, a town surveys the size of its wetland ecosystems. This equation estimates the total wetland area, in acres, over ti

nignag [31]

Answer:

When t=10, the town is predicted to have around 443 acres of wetlands.

At one time, the town had 740 acres of wetlands.

The wetland area in the town decreases by 5% per year.

Step-by-step explanation:

Given

$f(t) = 740 * (0.95)^t$

Required

The true statements

$(a)\ f(10) = 443$

We have:

$f(t) = 740 * (0.95)^t$

Substitute 10 for t

$f(10) = 740 * (0.95)^{10$

$f(10) = 443$

Hence, (a) is true

$(b)\ f(t) = 740$

We have:

$f(t) = 740 * (0.95)^t$

Substitute 740 for f(t)

$740 = 740 * (0.95)^t$

Divide through by 740

$1 = 0.95^t$

Express 1 as 0.95^0

$0.95^0 = 0.95^t$

Cancel out the bases

$0 = t$

$t = 0$

Hence, the area had 740 acres initially;

(b) is true

$(c)\ r = 5\%$

We have:

$f(t) = 740 * (0.95)^t$

Using the general formula

$f(t) = a * b^t$

By comparison:

$b = 0.95$

0.95 < 1 means that:

$b = 1 - r$ --- where r = rates

$0.95 = 1 - r$

Collect like terms

$r = 1 - 0.95$

$r = 0.05$

Express as percentage

$r = 5\%$

Hence, (c) is true

$(d)\ f(10) = 492$

In (a)

$f(10) = 443$

Hence, (d) is false

$(e)\ r = 95\%$

In (c)

$r = 5\%$ ---- decrement

Hence, (e) is incorrect

5 0

3 years ago

William has a length of wood that measures 4/5 of a foot. he cut that piece of wood into 8 equal lengths. what is the length of

lapo4ka [179]

(4/5) / 8 =
4/5 * 1/8 =
4/40 reduces to 1/10 ft

8 0

3 years ago