We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
Answer:
y = -x - 2
Step-by-step explanation:
y = mx + c
m = (-1-3)/(-1-(-5)) = -4/4 = -1
y = -x + c
(-1,-1)
-1 = -(-1) + c
c = -2
y = -x - 2
Answer:
a) Q(-2,1) is false
b) Q(-5,2) is false
c)Q(3,8) is true
d)Q(9,10) is true
Step-by-step explanation:
Given data is 
is predicate that 
then 
. where 
are rational numbers.
a)
when 
Here 
that is satisfied. Then
this is wrong. since 
That is 
Thus 
is false.
b)
Assume 
.
That is 
Here 
that is this condition is satisfied.
Then
this is not true. since 
.
This is similar to the truth value of part (a).
Since in both satisfied and 
for both the points.
c)
if 
that is 
and 
Here 
this satisfies the condition .
Then 
This also satisfies the condition .
Hence 
exists and it is true.
d)
Assume 
Here 
satisfies the condition
Then 
satisfies the condition .
Thus, 
point exists and it is true. This satisfies the same values as in part (c)
Answer:
80 cents
Step-by-step explanation:
