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3 years ago

(2x² + 3x - 5)(-x² + 7x + 2)

Mathematics

1 answer:

Alexxandr [17]3 years ago

6 0

Answer:

-2x^4 + 11x^3 + 30x^2 - 29x - 10

Step-by-step explanation:

1. Use the Distributive Property

(2x^2 + 3x - 5)(-x^2 + 7x + 2)

2. Remove parenthesis

2x^2(-x^2 + 7x + 2) + 3x(-x^7x+2) - 5(-x^2 + 7x + 2)

3. Collect like terms

-2x^4 + 14x^3 + 4x^2 - 3x^3 + 21x^2 + 6x + 5x^2 - 35x - 10

4. -2x^4 + 11x^3 + 30x^2 - 29x - 10

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Step-by-step explanation:

The trigonometric formula refers the two sides length of the triangle and it also consists of included angle to find out the area

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3 years ago

Read 2 more answers

On Tuesday, Karen finished all her chores in 3/4 of an hour. On Wednesday, she finished her chores in 5/12 of an hour. How much

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1 hour = 60 minutes

Tuesday: 60 divided by 4 = 15. Karen did it 3/4 of a hour so we multiply 15 by 4 which is 45. 45 equals 45 minutes. On Tuesday, Karen finished her chores in 45 minutes

Wednesday: first we divide 60 by 12 which is 5. 5 would equal 5 minutes. now we multiply 5 by 5 which is 25. Karen finished her chores in 25 minutes.

Answer: Karen finished her chores 20 minutes faster on Wednesday than Tuesday.

Hope this helps!

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2 years ago

The scale on a map of Virginia shows that 1 centimeter represents 30 miles. The actual distance from Richmond, VA to Washington,

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3 years ago

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3 years ago

The amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a stan

Ber [7]

Answer:

When sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

Step-by-step explanation:

We are given the amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a standard deviation of 0.35 hour.

Random samples of size 23 and 35 are drawn from the population and the mean of each sample is determined.

Here, $\mu$ = population mean = 7.5 hours

$\sigma$ = population standard deviation = 0.35 hour

Let $\bar X$ = sample mean

(a) The random samples of size of n = 23 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $\frac{0.35}{23}$ = 0.073

(b) The random samples of size of n = 35 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $} \frac{0.35}{\sqrt{35} }$ = 0.059

(c) So, as we can see that when sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

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3 years ago

(2x² + 3x - 5)(-x² + 7x + 2)​

(2x² + 3x - 5)(-x² + 7x + 2)