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3 years ago

A equation for one half and one six

Mathematics

2 answers:

nikitadnepr [17]3 years ago

7 0

Answer:

One half = 1/2

One six = 1/6

Step-by-step explanation:

to do one half, fill in the denominator _/2 and then half if 1/2!

To do one six, just fill in 1/6th !!

kobusy [5.1K]3 years ago

5 0

What exactly are you looking for?

-TTL

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The function ggg models the number of mosquitoes (in millions of mosquitoes) in a certain area as a function of rainfall (in cen

melomori [17]

Answer:

(Choice A) A More rainfall relates to more mosquitoes, as long as rainfall is less than 2 cm²

Step-by-step explanation:

The given function for the number of mosquitoes, (by analysis of the options) is, g(x) = 4·x - x²

Where;

x = The amount of rainfall

g(x) = The number of mosquitoes in millions

The given function can be expressed as follows;

g(x) = 4·x - x² + 0

The maximum point is given by g'(x) = d(4·x - x²)/dx = 4 - 2·x = 0

At the maximum (turning point), we have;

4 - 2·x = 0

4 = 2·x

x = 4/2 = 2

The level of rainfall that gives the maximum number of mosquitoes is, x = 2 cm²

The number of mosquitoes increases from zero rainfall up to the maximum number of 4 million mosquitoes at 2 cm² rainfall and then decreases to zero as the rainfall increases further more than 2 cm², as shown in the attached graph of the function g(x) that models the number of mosquitoes created with MS Excel

Therefore, the true statement is (Choice A) more rainfall relates to more mosquitoes, as long as (the level of) rainfall is less than (the maximum) 2 cm².

6 0

3 years ago

A major DVD rental chain is considering opening a new store in an area that currently does not have any such stores. The chain w

Mariana [72]

<h2>Answer with explanation:</h2>

Let p be the population proportion .

Then, $p=\dfrac{5000}{20000}=0.25$

According to the given information, we have

$a)\ \text{Null hypothesis }H_0: p=0.25\\\\b)\ \text{Alternative hypothesis} H_a: p\neq0.25$ , since alternative hypothesis is two-tailed , so the hypothesis test is a two-tail test.

Since sample size is large (n> 30), we use z-test.

Let us consider 95% confidence i.e. $\alpha=0.05$ .

c) Critical value = $z_{\alpha/2}=\pm1.96$

Sample proportion : $\hat{p}=\dfrac{96}{300}=0.32$

d) Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

i.e. $z=\dfrac{0.32-0.25}{\sqrt{\dfrac{0.25(0.75)}{300}}}=2.8$

e) P-value (for two-tail) : $2(Pz>2.8)=0.0051103$

f) P-value is the probability value that we have falsely rejected the null hypothesis.

g) Since observed z-value (2.8) does not lie in critical interval (-1.96, 1.96), it means the null hypothesis is rejected.

7 0

3 years ago

Four pipes can fill a tank in 70 minutes.how long will it take to fill the tank with 7 pipes are used

mina [271]

Set it up like a ratio: pipes on the top and minutes on the bottom. Therefore, your ratio would be 4/70 = 7/x. Cross-multiply to get 4x=490 and x = 122.5 minutes. Change that to hours if you'd like by dividing by 60!

7 0

3 years ago

A portfolio's value increases by 17% during a financial boom and by 7% during normal times. It decreases by 11% during a recessi

sdas [7]

Answer:

100%(start)+17%(boom)+7%(normal)=124%

124%-11%(recession)=113%

7 0

4 years ago

A rectangular "standing-only" section at the venue changes size as increases in order to manage the flow of people. Let represen

wariber [46]

Answer:

The rate of change of the area of the section with respect to time = 12 ft²/hr

Step-by-step explanation:

Complete Question

A rectangular "standing only" section at the venue changes size as t increases in onder to manage the flow of people, let x represent the length, in feet, of the section, and let y represent the width, in feet of the section. The length of the section is increasing at a rate of 6 feet/hour and the width of the section is decreasing at a rate of 3 feet/hour. What is the rate of change of the area of the section with respect to time when x=16 & y=10?

The area of a rectangular section is given as

Area = Length × Width

Area = A

Length = x

Width = y

A = xy

We now nred the time Rate of change of the area. So, we take the time derivative of both sides.

A = xy

(d/dt) (A) = (d/dt) (xy)

Using product rule for the Right hand side

(dA/dt) = x(dy/dt) + y(dx/dt)

- The length of the section is increasing at a rate of 6 feet/hour, that is, (dx/dt) = 6 ft/hr

- The width of the section is decreasing at a rate of 3 feet/hour, that is, (dy/dt) = -3 ft/hr (minus sign because it is decreasing)

x = 16 ft

y = 10 ft

(dA/dt) = x(dy/dt) + y(dx/dt)

(dA/dt) = (16)(-3) + (10)(6) = -48 + 60 = 12 ft²/hr

Hope this Helps!!!

5 0

3 years ago