Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90



has a pvalue of 0.9649
X = 82



has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
2ab - 3a = a.(2b-3)
now the same thing
let's say n=1
a.(2b-3) + n.(2b-3) = (2b-3).(a+n)
Understood?
Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78
Answer:
Is there a picture of it?
Step-by-step explanation:
Answer:
44u-36
Step-by-step explanation:
42u-36+2u
44u-36