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3 years ago

What is the sum of interior angles of a convex nonagon

Mathematics

1 answer:

zmey [24]3 years ago

8 0

A nonagon has 9 sides, so n = 9

S = sum of the interior angles
S = 180*(n-2)
S = 180*(9-2)
S = 180*7
S = 1260

Answer is choice B

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Nick wrote the function p(x) = 17 + 42x – 7x2 in vertex form. His work is below.

Finger [1]

Answer:

step 3

Step-by-step explanation:

he should have subtracted 9 to the outside.

whatever you do to the inside you must do to the opposite to the outside

so your final form must be -7(x-3)^2 + 8

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2 years ago

Which quantity is use to generate the error bars on a graph?

rodikova [14]

The error bars are used to indicate the variability of the data presented in a graph.

There are several quantities that can be used to generate error bars in the graph. These are:
standard deviation
standard error
confidence interval

Usually, one standard deviation above and below the mean is used although it is advised to indicate which variability data is used to generate the error bars in the graph since the 3 quantity given are not equal.

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3 years ago

What is the missing digit? LOTS OF POINTS!

RideAnS [48]

Answer:

The missing digits are 3 and 1.

Step-by-step explanation:

6+3÷3-1=2

9÷3-1=2

3-1=2

3 0

3 years ago

Read 2 more answers

5. Does the following table represent a function? Explain.

lys-0071 [83]

Answer:

Yes

Step-by-step explanation:

A function cannot have the same x values but can have the same y values. Because all of the x-values are different, this table represents a function.

If this has helped please mark as brainliest

8 0

3 years ago

A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o

Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let X = number of students who have laptops.

The probability of a student having a laptop is, P (X) = p = 0.37.

A random sample of n = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable X follows a Binomial distribution with parameters n and p.

The mean and standard deviation of a binomial random variable X are:

$\mu=np\\\sigma=\sqrt{np(1-p)}$

Compute the mean of the random variable X as follows:

$\mu=np=30\times0.37=1.11$

The mean of the random variable X is 1.11.

Compute the standard deviation of the random variable X as follows:

$\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836$

The standard deviation of the random variable X is 0.836.

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3 years ago