1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
X=7, y=6. that’s your answer!
Answer:
Emilio will have both activities again on the same day after 90 days from this Saturday.
Step-by-step explanation:
<em>To solve this question list the multiples of 30 and 9 to find the first common multiple because the two activities will happen again in </em><em>a number divisible by both 30 and 9.</em>
∵ The multiples of 30 are: 30, 60, 90, 120, ............
∵ The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, .....
→ The common multiple is 90
∴ The common multiple of 30 and 9 is 90
→ That means the activities will meet again after 90 days from
this Saturday
Emilio will have both activities again on the same day after 90 days from this Saturday.
Answer:
64.6 km/h
Step-by-step explanation:
18:14 = 18h 14'
1h = 60'
18h = 17h + 60'
18h14' = 17h + 60' ´14' = 17h 74'
then:
17h 74'
-17h 22'
= 0h 52'
the train travelled 56km at 52 minutes
56km/52minutes
1 hour = 60 minutes
52 minutes = 52/60 = 0.86667 hours
then:
56km/52minutes = 56km/0.86667hours
= 64.615 km/hours
Step-by-step explanation:
All has been answered... send me any questions at comments
