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Ket [755]
3 years ago
12

Identify the solution of the system -2x-4y=1 12y=-6x-3

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0
-2x - 4y = 1
<u>12y</u> = <u>-6x - 3</u>
 12         12
   y = -0.5x - 0.25

-2x - 4(-0.5x - 0.25) = 1
-2x + 2x + 1 = 1
0x + 1 = 1
<u>     - 1  - 1</u> 
       <u>0x</u> = <u>0</u>
        0     0
         x = 0
-2(0) - 4y = 1
0 - 4y = 1
<u>-4y</u> = <u>1</u>
 -4    -4
   y = -0.25
(x, y) = (0,-0.25)
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The range of the function RK) = R +26+1 İS {25, 643. What is the function's domain?
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3 years ago
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NEED HELP ON ALL OF THESE PLEASE
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Answer:

1) 2670m^2

2) 4718 in^2

3) 4730 ft^2

4) 7900cm^2

5) 11 542mm^2

6) 3740m^2

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8) 2824 ft^2

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Step-by-step explanation:

Area of a rectangular prism = 2wl + 2lh + 2hw

Where,

w = width

l = length

h = height

1) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 10m; l = 31m; w = 25m

Area = 2(25m)(31m) + 2(31m)(10m) + 2(10m)(25m)

= 2(775m^2) + 2(310m^2) + 2(250m^2)

= 1550m^2 + 620m^2 + 500m^2

= 2670m^2

2) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 21 in; l = 35 in; w = 29 in

Area = 2(29in)(35in) + 2(35in)(21in) + 2(21in)(29in)

= 2(1015in^2) + 2(735in^2) + 2(609in^2)

= 2030in^2 + 1470in^2 + 1218in^2

= 4718 in^2

3) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 19 ft; l = 39ft; w = 28ft

Area = 2(28ft)(39ft) + 2(39ft)(19ft) + 2(19ft)(28ft)

= 4730 ft^2

4) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 24,cm; l = 49cm; w = 38cm

Area = 2(38cm)(49cm) + 2(49cm)(24cm) + 2(24cm)(38cm)

= 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

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