For this case we must solve a system of two equations with two unknowns, given by "x" and "y".
We have:

We multiply (2) by -1:

We add (1) and (3):

Clearing x:

We substitute
in (2)

Thus, the solution of the system is 
Answer:
The solution of the system is 
Answer:
B
Step-by-step explanation:
If you take a lokk at the picture I used an online algebra calculator to check my answer against to gurantee the corectness of my answer for you.
Answer:
Sorry it's acually (h+3)(h-9)
Answer:

Step-by-step explanation:
Given expression is,
f(x) = 8x³ - 6x² - 36x + 27
For zeros of the function,
f(x) = 0
8x³ - 6x² - 36x + 27 = 0
2x²(4x - 3) - 9(4x - 3) = 0
(2x² - 9)(4x - 3) = 0
(2x² - 9) = 0
x² = 
x = 
x = 
Or (4x - 3) = 0
x = 
Therefore, all zeros of the given functions are
.