Question

Answer 35 and 36 fully with the way you did it not only answer!!

Answer 1

35a. We're asked to compute the ratio between the enlarged width and the original width. So we literally perform the operation:

$6.5\div 3.5 \approx 1.86$

35b. If the order is wrong the image would be shrunk instead of enlarged, with a ratio of $3.5\div 6.5$

36. We know that

$\dfrac{p}{q}=\dfrac{2}{3}$

Observe that

$\dfrac{6p}{2q}=\dfrac{6}{2}\cdot\dfrac{p}{q}=3\cdot\dfrac{p}{q}=3\cdot\dfrac{3}{2}=\dfrac{9}{2}$