what kind of car is this ?
Answer: 122 ft
<u>Step-by-step explanation:</u>
s = r Ф (Ф must be in radians)
Given: r = 50
Ф = 140°
![\dfrac{140^o\pi}{180^o}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B140%5Eo%5Cpi%7D%7B180%5Eo%7D%3Dx)
![\dfrac{7\pi}{9}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B7%5Cpi%7D%7B9%7D%3Dx)
![s=50\bigg(\dfrac{7\pi}{9}\bigg)\\\\\\.\quad =\dfrac{350\pi}{9}\\\\\\.\quad =122\ ft](https://tex.z-dn.net/?f=s%3D50%5Cbigg%28%5Cdfrac%7B7%5Cpi%7D%7B9%7D%5Cbigg%29%5C%5C%5C%5C%5C%5C.%5Cquad%20%3D%5Cdfrac%7B350%5Cpi%7D%7B9%7D%5C%5C%5C%5C%5C%5C.%5Cquad%20%3D122%5C%20ft)
Answer with Step-by-step explanation:
In case of Bernoulli trails
The probability that a random variable occurs 'r' times in 'n' trails is given by
![P(E)=\binom{n}{r}p^r(1-p)^{n-r}](https://tex.z-dn.net/?f=P%28E%29%3D%5Cbinom%7Bn%7D%7Br%7Dp%5Er%281-p%29%5E%7Bn-r%7D)
where
'p' is the probability of success of the event
Part a)
probability that no contamination occurs can be found by putting r = 0
Thus we get
![P(E_1)=\binom{5}{0}0.1^0(1-0.1)^{5}=0.5905](https://tex.z-dn.net/?f=P%28E_1%29%3D%5Cbinom%7B5%7D%7B0%7D0.1%5E0%281-0.1%29%5E%7B5%7D%3D0.5905)
part b)
The probability that at least 1 contamination occurs is given by
![P(E)=1-(1-p)^{n}](https://tex.z-dn.net/?f=P%28E%29%3D1-%281-p%29%5E%7Bn%7D)
Applying values we get
![P(E_2)=1-(1-0.1)^{5}=0.4096](https://tex.z-dn.net/?f=P%28E_2%29%3D1-%281-0.1%29%5E%7B5%7D%3D0.4096)
5x-30+5x=180 due to RS and TS being congruent,
10x-30=180
10x=210
x=21
R(9,0)
S(8,-4)
T(7,4)
V(6,0)