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Rufina [12.5K]
3 years ago
5

F(n) = 4(n-1) + 7fine the first three(3) terms in the sequence show all work​

Mathematics
2 answers:
vladimir1956 [14]3 years ago
8 0
........................................
lubasha [3.4K]3 years ago
4 0

Answer:

f(n) = 4(n-1) + 7

First term

f(1) = 4(1-1) +7 = 0 + 7 = 7

Second term

f(2) = 4(2-1) + 7

= 4(1) + 7 = 4 + 7 =11

Third term

f(3) = 4(3-1) + 7

= 4(2) + 7

= 8 + 7 = 15

Therefore the first three terms of the sequence are 7, 11 and 15.

Hope this helps

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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
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Answer:

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Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

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so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

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\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

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